Worked formula example
Ohm's Law Examples
With 0.25 A through 48 ohms, the voltage is 12 V. The example keeps the problem, given values, formula, substitution, and copyable result sentence together so the calculator page can be opened only when values or units change.
Worked examples
| Step | Value |
|---|---|
| Problem | Find voltage when current and resistance are known. |
| Given values | I = 0.25 A, R = 48 ohms |
| Formula | V = I x R |
| Calculation | V = 0.25 x 48 = 12 V |
| Copyable result sentence | With 0.25 A through 48 ohms, the voltage is 12 V. |
| Step | Value |
|---|---|
| Problem | Find current when voltage and resistance are known. |
| Given values | V = 24 V, R = 12 ohms |
| Formula | I = V / R |
| Calculation | I = 24 / 12 = 2 A |
| Copyable result sentence | With 24 V across 12 ohms, the current is 2 A. |
| Step | Value |
|---|---|
| Problem | Find power after solving an ohmic load. |
| Given values | V = 12 V, I = 0.25 A |
| Formula | P = V x I |
| Calculation | P = 12 x 0.25 = 3 W |
| Copyable result sentence | A 12 V load at 0.25 A dissipates 3 W. |
Copyable result sentence
With 0.25 A through 48 ohms, the voltage is 12 V.
Common mistakes
- Dropping units before the ohm's law examples substitution.
- Rounding the ohm's law examples calculation before the final step.
- Using a formula variant that does not match the known values for ohm's law examples.